# Electronic Engineering Applications of Two-Port Networks

## Electronic engineering applications of two-port networks - Howard Bruce Gatland - Google книги

Asked 2 years, 4 months ago. Active 2 years, 4 months ago.

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Viewed times. They relate V1 as a function of I1 and V2. And I2 as a function of I1 and V2. And these mathematical equations are modelled as the following circuits: My question is about the motivation of the idea of writing those two equations at the beginning.

## ISBN 13: 9780080180694

Question: The first equation relates V1 to I1 and V2. Why two independent relations are added to equate V1? Edit: Here is the superposition principle: But this principle is turning off "voltage sources". HelpMee HelpMee 1 1 gold badge 12 12 silver badges 34 34 bronze badges. Also, not all resistors are linear, and a circuit containing a nonlinear resistor is not a linear circuit. But my question here regarding my figures, should V2 be an independent source or can it be an output to employ superposition?

I mean in that two port network model is V2 a source or output?

- Isaiah 24-27 and the Origin of Apocalyptic (Harvard Semitic Monographs, No. 11.)?
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- Electronic Engineering Applications of Two-Port Networks.

Because according to the theorem to zero V2 it must be a source isnt it? But on the other hand it looks like an input output network..

The 2-port doesn't know whether the voltage across its terminals is caused by an independent source or something else. The key is this: To characterize a two-port network requires that we relate the terminal quantities V1, V2, I1, and I2, out of which two are independent. Depending which you pick, there's a different name for the matrix that relates them. Edit I guess you are trying to focus on this part of your question? Edit 2 You found this definition of the superposition principle: This is simply wrong, or at least it's a very incomplete version of the superposition principle.

The Photon The Photon Im asking why we have the right to add two independent relations in a linear system?

## Energy storage within two-port networks.

And your answer is "it is because the system is linear". Kind of circular to me. Skip to Main Content. A not-for-profit organization, IEEE is the world's largest technical professional organization dedicated to advancing technology for the benefit of humanity. Use of this web site signifies your agreement to the terms and conditions.

Personal Sign In. For IEEE to continue sending you helpful information on our products and services, please consent to our updated Privacy Policy. Email Address. In looking over information online, I can't find any place else that places this same restriction on the circuits in such a network, at least not in so many words.

### Symmetrical two‐port networks: An eigenspace perspective

So I'd like to get some of your thoughts on the matter. Feb 17, 2. May 10, It seems like a strange statement. When studying passive two ports it is usual to require that there are no internal sources of power, this allows you to assert that the power leaving the two port won't exceed the incident power, which leads to useful properties of the various circuit matrices.

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I suspect this is what they mean. No reactive power would mean studying resistive circuits only - is that what they are doing? The best thing to do is to scan the chapter and see where they use this assumption, if it is well written this should be clear. Feb 17, 3. Feb 18, 4. Aug 27, 6, 6, Do you think they are implying no 'initial' energy storage and the network reactive elements are at a zero energy state before any external sources are connected.

Feb 18, 5. Feb 18, 6. Nov 23, 7, 6, Feb 19, 7.

Mar 6, 5, Perhaps that no independent energy sources may 'reside' in any 2-port.